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超短的0MS的代码#include <cstdio>
typedef long long ll;
struct AC{
ll c,y;
}r[11000];
ll n,s;
int main(){
scanf("%d%d",&n,&s);
for (int i=1;i<=n;i++)
scanf("%d%d",&r[i].c,&r[i].y);
ll ans=0,min=1<<30;
for (int i=1;i<=n;i++){
min+=s;
if (min>r[i].c)
min=r[i].c;
ans+=min*r[i].y;
}
printf("%lld",ans);
return 0;
}
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