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超短的0MS的代码#include <cstdio> typedef long long ll; struct AC{ ll c,y; }r[11000]; ll n,s; int main(){ scanf("%d%d",&n,&s); for (int i=1;i<=n;i++) scanf("%d%d",&r[i].c,&r[i].y); ll ans=0,min=1<<30; for (int i=1;i<=n;i++){ min+=s; if (min>r[i].c) min=r[i].c; ans+=min*r[i].y; } printf("%lld",ans); return 0; } Followed by:
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