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c++ 除了快排,另一种方法也是0ms,弱弱纪念下代码可能有很多能优化的地方,主要是思路:
ACGT三次循环,第一次循环,将所有的A移动到最前面的位置,其他类似,值得注意当ACG排好就不用排T了,此外每次移动查看后面的字符与当前是否一样,可以减少循环总次数,想法和快排一样。PS:0ms
#include<iostream>
#include<string>
#include<vector>
#include<map>
#include<math.h>
#include<algorithm>
using namespace std;
int getIndex(const char a)
{
switch (a)
{
case 'A':
return 0;
case 'C':
return 1;
case 'G':
return 2;
case 'T':
return 3;
}
}
int getInt(const string s)
{
static string acgt_array[4] = { "A", "C", "G", "T" };
int size_array[4] = {}, index_array[4] = {};
string s_copy(s);
int result = 0;
for (string::iterator i = s_copy.begin(); i != s_copy.end(); i++)
{
size_array[getIndex(*i)] ++;
}
//计算
for (int j = 0; j < 3; j++)
{
string temp_copy = "";
for (int i = 0; i < s_copy.length();)
{
int sum = 0, temp_result = 0;
while (i < s_copy.length() && getIndex(s_copy[i]) == j)
{
if (sum == 0)
{
temp_result = i - index_array[j];
}
i++;
sum++;
index_array[j] ++;
}
if (sum)
{
result += sum* temp_result;
}
else
{
temp_copy += s_copy[i];
i++;
}
}
s_copy = temp_copy;
}
return result;
}
int main()
{
int length, size;
cin >> length >> size;
map<int, string> map_data;
string temp = "";
int index = 0;
while (index < size)
{
cin >> temp;
index++;
int sum = getInt(temp);
if (map_data[sum] == "")
{
map_data[sum] = temp;
}
else
{
map_data[sum] += temp;
}
}
for (map<int, string>::iterator it = map_data.begin(); it != map_data.end(); it++)
{
temp = (*it).second;
int length_temp = temp.length();
for (int i = 0; i < length_temp / length; i++)
{
string mm = string(temp.begin() + i * length, temp.begin() + (i + 1) * length);
cout << mm << endl;
}
}
system("pause");
return 0;
}
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