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变换公式后注意精度就很简单了http://blog.csdn.net/luckcircle/article/details/54808678
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#include<iostream>
#include<cstdio>
#include<cmath>
using namespace std;
int main(){
double n,p,k;
while(scanf("%lf %lf",&n,&p)!=EOF){
k=(double)pow(p,1.0/n);
printf("%.0lf\n",k);
}
}
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