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Re:哪里错了?In Reply To:哪里错了? Posted by:fanyaofeng2015 at 2016-11-14 23:12:24 > #include <stdio.h> > #include <string.h> > #include <algorithm> > > using namespace std; > > int cmp(int a,int b) > { > return a < b; > } > > int Plus(int n) > { > int i; > int val = 1; > for (i = 0;i < n;i ++) > { > val = val * 10; > } > return val; > } > > int main() > { > int i,n,j,m,sum,k,l,flag; > char strings[20]; > int num[100000]; > > scanf("%d",&n); > memset(num,0,sizeof(num)); > flag = 0; > for (j = 0;j < n;j ++) > { > scanf("%s",strings); > num[j] = 0; > for (i = 0;strings[i] != '\0';i ++) > { > m = -1; > if((strings[i] >= '0') && (strings[i] <= '9')) > { > m = strings[i] - '0'; > } > else if ((strings[i] == 'A') || (strings[i] == 'B') || (strings[i] == 'C')) > { > m = 2; > } > else if ((strings[i] == 'D') || (strings[i] == 'E') || (strings[i] == 'F')) > { > m = 3; > } > else if ((strings[i] == 'G') || (strings[i] == 'H') || (strings[i] == 'I')) > { > m = 4; > } > else if ((strings[i] == 'J') || (strings[i] == 'K') || (strings[i] == 'L')) > { > m = 5; > } > else if ((strings[i] == 'M') || (strings[i] == 'N') || (strings[i] == 'O')) > { > m = 6; > } > else if ((strings[i] == 'P') || (strings[i] == 'R') || (strings[i] == 'S')) > { > m = 7; > } > else if ((strings[i] == 'T') || (strings[i] == 'U') || (strings[i] == 'V')) > { > m = 8; > } > else if ((strings[i] == 'W') || (strings[i] == 'X') || (strings[i] == 'Y')) > { > m = 9; > } > > if (m != -1) > { > num[j] = num[j] * 10 + m; > } > } > } > > sort(num,num + n,cmp); > > for (i = 0;i < n;i ++) > { > sum = 1; > l = 6; > for (j = i + 1;j < n;j ++) > { > if (num[i] == num[j]) > { > sum++; > } > else > { > break; > } > } > > if (sum > 1) > { > flag = 1; > for (k = 0;k < 3;k ++) > { > printf("%d",num[i] / Plus(l)); > num[i] = num[i] % Plus(l); > l--; > } > printf("-"); > for (k = 3;k < 7;k ++) > { > printf("%d",num[i] / Plus(l)); > num[i] = num[i] % Plus(l); > l--; > } > printf(" %d\n",sum); > } > > i = j - 1; > } > > if (flag == 0) > { > printf("\nNo duplicates.\n"); > } > > return 0; > } Followed by: Post your reply here: |
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