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虽然是水题,代码也要精简,来个191B的小代码PRS三个字母换成2进制,取后三位刚好是023,以此为索引打表(3表示平局,2表示赢,1表示输)
main() {
char s[80], t[80], *p, *q, c, m[] = "3321333313322313";
int x[3];
while (gets(s) && *s != 69) {
gets(t);
p = s;
q = t;
*x = x[1] = 0;
while (c = *p++)x[m[(c & 3) * 4 + (*q++ & 3)] - 49]++;
printf("P1: %d\nP2: %d\n", x[1], *x);
}
}
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