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公式是n(n+1)(n+2)(n+3)/8

Posted by Eov_Second at 2016-12-02 12:01:16 on Problem 3086
n(n+3)和(n+1)(n+2)两个都是偶数,先计算出来各自除2,最后乘起来再除2
n(n+3) = n^2+3n
(n+1)(n+2)=n^2+3n+1

所以令a=n(n+3)/2
则最后结果是a(a+1)/2

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