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H2O#include <stdio.h> int has[30][30]; int mxx,mxy,cnt; int solve(){ int res = 0; while(cnt>0){ int pos = 1; for(int i = 1; i <= mxx; i++){ int mxPos = 0; for(int j = mxy; j >= pos; j--){ if(has[i][j]){ mxPos = j; break; } } if(mxPos == 0) continue; for(int j = pos; j <= mxPos; j++){ if(has[i][j]){ has[i][j] = 0; cnt--; } } pos = mxPos; } res++; } return res; } int main(int argc, char **argv){ while(1){ int a,b,c,d; mxx=0,mxy=0,cnt=0; scanf("%d%d",&a,&b); if(a==-1) break; for(int i = 1; i < 30; i++){ for(int j = 1; j < 30; j++){ has[i][j] = 0; } } while(1){ scanf("%d%d",&c,&d); has[a][b] = 1; cnt++; if(a>mxx) mxx=a; if(b>mxy) mxy=b; if(!c) break; a=c; b=d; } printf("%d\n", solve()); } return 0; } Followed by: Post your reply here: |
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