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Re:可以尝试一下 高精度+泰勒展开。。。。In Reply To:可以尝试一下 高精度+泰勒展开。。。。 Posted by:JiaJunpeng at 2016-09-08 15:01:13 > 普通的辛普森或者牛顿莱布尼茨 时间太紧。。。 利用 fn(x0)=(fn-1(x0+eps)-fn-1(x0))/eps 来求f(x)的 N阶导数值 这个需要高精度 Followed by: Post your reply here: |
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