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20行代码~#include<iostream> #include<cstdio> #include<algorithm> using namespace std; const int MAXN=2000+10; int d[MAXN][MAXN],a[MAXN]; int main() { int n; scanf("%d",&n); for(int i=1;i<=n;i++) scanf("%d",&a[i]); for(int i=1;i<=n;i++) d[i][i]=n*a[i]; for(int i=n-1;i>0;i--) for(int j=i+1;j<=n;j++) d[i][j]=max(d[i+1][j]+(n-j+i)*a[i],d[i][j-1]+(n-j+i)*a[j]); printf("%d\n",d[1][n]); return 0; } Followed by: Post your reply here: |
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