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又是个纯净水,连着几个大水题怎么就是没人做#include <iostream>
#include <stdio.h>
#include <string>
using namespace std;
double H2O[5][3] = {{0.1, 0.06, 0.02},
{0.25, 0.15, 0.05},
{0.53, 0.33, 0.13},
{0.87, 0.47, 0.17},
{1.44, 0.80, 0.30}};
inline int mx(int a, int b){
return a>b ? a : b;
}
inline int mn(int a, int b){
return a<b ? a : b;
}
inline int ws(int n){
if(n < 10) return 1;
if(n < 100) return 2;
if(n < 1000) return 3;
return 4;
}
int main() {
while(1){
string str;
getline(cin, str);
if(str[0] == '#') break;
int dist = str[0] - 'A';
int t1 = 0, t2 = 0, t3 = 0;
int startH = 10 * (str[11]-'0') + str[12] - '0',
startM = 10 * (str[14]-'0') + str[15] - '0',
endH = 10 * (str[17]-'0') + str[18] - '0',
endM = 10 * (str[20]-'0') + str[21] - '0';
int start = startH * 60 + startM, end = endH * 60 + endM;
if(start < end){
for(int j = start; j < end; j++){
if(j >= 480 && j < 1080) t1++;
else if(j >= 1080 && j < 1320) t2++;
else t3++;
}
}
else if(start > end){
for(int j = end; j < start; j++){
if(j >= 480 && j < 1080) t1++;
else if(j >= 1080 && j < 1320) t2++;
else t3++;
}
t1 = 600-t1, t2 = 240-t2, t3 = 600-t3;
}
else{
t1 = 600, t2 = 240, t3 = 600;
}
double price = H2O[dist][0]*t1 + H2O[dist][1]*t2 + H2O[dist][2]*t3;
printf(" ");
for(int i = 2; i <= 9; i++){
printf("%c", str[i]);
}
int ws1 = ws(t1), ws2 = ws(t2), ws3 = ws(t3);
for(int i = 0; i < 6-ws1; i++) printf(" ");
printf("%d", t1);
for(int i = 0; i < 6-ws2; i++) printf(" ");
printf("%d", t2);
for(int i = 0; i < 6-ws3; i++) printf(" ");
printf("%d", t3);
printf(" %c", str[0]);
int p_ = (int)price;
int wsp = ws(p_);
for(int i = 0; i < 5-wsp; i++) printf(" ");
printf("%.2lf\n", price);
}
return 0;
}
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