| ||||||||||
| Online Judge | Problem Set | Authors | Online Contests | User | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest | |||||||||
最大流水过了#include <stdio.h>
#include <queue>
using namespace std;
int h, w;
const int SSS = 2147483647;
const int TTT = -2147483648;
int N, M, oddNum, evenNum;
int oddRow[204], oddCol[204], evenRow[204], evenCol[204];
int bh[50][50] = {0};
int graph[204][204] = {{0}};
bool s[204] = {false}, t[204] = {false};//false表示可用
void init(){
for(int i = 0; i < 204; i++)
for(int j = 0; j < 204; j++)
graph[i][j] = 0;
for(int i = 0; i < 204; i++) s[i] = 0;
for(int i = 0; i < 204; i++) t[i] = 0;
for(int i = 0; i < 50; i++)
for(int j = 0; j < 50; j++)
bh[i][j] = 0;
oddNum = 0, evenNum = 0;
}
bool pushflow(){
//如果push不了,返回false
queue<int> bfs;
bool getT = false;
int noT;
int S[204] = {0}, T[204] = {0};
for(int i = 1; i < N; i++){
if(!s[i]){
S[i] = SSS;
bfs.push(i);
}
}
while(!bfs.empty()){
int cur = bfs.front();
bfs.pop();
if(cur > 0){
//是s这边的点
for(int j = 1; j <= M; j++){
if(graph[cur][j] == 1 && T[j] == 0){
bfs.push(-j);
T[j] = cur;
}
}
}
else{
//是t这边的点
int j = -cur;
if(!t[j]){
getT = true;
noT = cur;
break;
}
for(int i = 1; i < N; i++){
if(graph[i][j] == -1 && S[i] == 0){
bfs.push(i);
S[i] = cur;
}
}
}
}
if(!getT) return false;
t[-noT] = true;
int TtoS = 1;
while(1){
if(TtoS){
//push路径当前从S端到T端
int noS = T[-noT];
graph[noS][-noT] = -1;
noT = noS;
}
else{
//从T端到S端
int noS = S[noT];
if(noS == SSS){
s[noT] = true;
break;
}
graph[noT][-noS] = 1;
noT = noS;
}
TtoS = 1 - TtoS;
}
return true;
}
int main() {
int cases;
scanf("%d", &cases);
for(int i = 0; i < cases; i++){
scanf("%d%d", &h, &w);
init();
for(int j = 0; j < h; j++){
char s[50];
scanf("%s", s);
for(int k = 0; k < w; k++){
if(s[k] == '*') {
if((j+k)%2==0){
evenNum ++;
bh[j][k] = evenNum;
evenRow[evenNum] = j;
evenCol[evenNum] = k;
if(j > 0 && bh[j-1][k] > 0){
graph[bh[j-1][k]][bh[j][k]] = 1;
}
if(k > 0 && bh[j][k-1] > 0){
graph[bh[j][k-1]][bh[j][k]] = 1;
}
}
else{
oddNum ++;
bh[j][k] = oddNum;
oddRow[oddNum] = j;
oddCol[oddNum] = k;
if(j > 0 && bh[j-1][k] > 0){
graph[bh[j][k]][bh[j-1][k]] = 1;
}
if(k > 0 && bh[j][k-1] > 0){
graph[bh[j][k]][bh[j][k-1]] = 1;
}
}
}
}
}
N = oddNum + 1, M = evenNum;
int cnt = 0;
while(pushflow()){cnt++;}
printf("%d\n", oddNum+evenNum-cnt);
}
return 0;
}
Followed by: Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator