Online JudgeProblem SetAuthorsOnline ContestsUser
Web Board
Home Page
F.A.Qs
Statistical Charts
Problems
Submit Problem
Online Status
Prob.ID:
Register
Update your info
Authors ranklist
Current Contest
Past Contests
Scheduled Contests
Award Contest
User ID:
Password:
  Register

Re:二维树状数组 TLE 的同学们注意了 ! 下标从0开始。 附上测试数据。

Posted by Gazer_Fri at 2016-07-26 15:10:29 on Problem 1195
In Reply To:二维树状数组 TLE 的同学们注意了 ! 下标从0开始。 附上测试数据。 Posted by:lanjiongjiang at 2014-08-10 16:23:40
> TLE 的同学们注意了。下标从0开始。附上测试数据。
> 
> in
> 0 1
> 1 0 0 28766
> 2 0 0 0 0
> 1 0 0 -2826
> 2 0 0 0 0
> 1 0 0 -587
> 2 0 0 0 0
> 1 0 0 1017
> 2 0 0 0 0
> 1 0 0 -17234
> 2 0 0 0 0
> 1 0 0 19618
> 2 0 0 0 0
> 1 0 0 -2237
> 2 0 0 0 0
> 1 0 0 -9192
> 2 0 0 0 0
> 1 0 0 -11132
> 2 0 0 0 0
> 1 0 0 1842
> 2 0 0 0 0
> 3
> 
> out
> 28766
> 25940
> 25353
> 26370
> 9136
> 28754
> 26517
> 17325
> 6193
> 8035
> 
> 过了这组应该就没有问题了。
> 
> //////////////My AC Code///////////////////
> /*  641MS	C++  */
> /*  1079MS	G++  */
> #include <cstdio>
> #include <iostream>
> #include <cstring>
> #include <cmath>
> #include <string>
> #include <algorithm>
> #include <queue>
> #include <stack>
> using namespace std;
> 
> const int MAXN = 1050;
> int s[MAXN][MAXN];
> int lowbit[MAXN];
> int n;
> 
> int sum(int x, int y)
> {
>     int res = 0;
>     for(int i = x; i > 0; i -= lowbit[i])
>         for(int j = y; j > 0; j -= lowbit[j])
>             res += s[i][j];
>     return res;
> }
> 
> int main()
> {
>     //freopen("in.txt", "r", stdin);
>     //freopen("out.txt", "w", stdout);
>     int op;
>     int x, y, v;
>     int x1, y1, x2, y2;
>     for(int i = 1; i <= MAXN; i++)
>     {
>         lowbit[i] = i&-i;
>     }
>     while(1)
>     {
>         scanf("%d", &op);
>         if(op == 1)
>         {
>             scanf("%d %d %d", &x, &y, &v);
>             x++; y++;
>             for(int i = x; i <= n; i += lowbit[i])
>                 for(int j = y; j <= n; j += lowbit[j])
>                     s[i][j] += v;
>         }
>         else if(op == 2)
>         {
>             scanf("%d %d %d %d", &x1, &y1, &x2, &y2);
>             x1++; y1++; x2++; y2++;
>             int ans = sum(x2, y2)+sum(x1-1, y1-1)-sum(x1-1, y2)-sum(x2, y1-1);
>             printf("%d\n", ans);
>         }
>         else if(op == 0)
>         {
>             scanf("%d", &n);
>             memset(s, 0, sizeof(s));
>         }
>         else
>             break;
>     }
>     return 0;
> }
> 
然而我依旧WA。。。注意0了。。

Followed by:

Post your reply here:
User ID:
Password:
Title:

Content:

Home Page   Go Back  To top


All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator