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用dijkstra可以AC,Floyd会超时#include <iostream> #include <cstdio> #include <cstring> #include <string> #include <vector> #include <algorithm> #include <set> #include <map> #include <bitset> #include <cmath> #include <queue> #include <stack> using namespace std; const int INF=1<<25; const int maxn=1010; struct edge{ int to,cost; }; typedef pair<int,int> P; vector<edge> g[maxn]; int d[maxn]; int dp[maxn][maxn]; int n,m,x; void dijkstra(int s) { priority_queue<P, vector<P>, greater<P> > que; fill(d,d+n+1,INF); d[s]=0; que.push(P(0,s)); while(!que.empty()){ P p=que.top(); que.pop(); int v=p.second; if(d[v]<p.first) continue; for(int i=0;i<g[v].size();i++){ edge e=g[v][i]; if(d[e.to]>d[v]+e.cost){ d[e.to]=d[v]+e.cost; que.push(P(d[e.to],e.to)); } } } } int main() { while(cin>>n>>m>>x) { for(int i=0;i<=n;i++) for(int j=0;j<=n;j++) dp[i][j]=INF; for(int i=0;i<m;i++) { edge e; int a,b,num; scanf("%d%d%d",&a,&b,&num); e.to=b,e.cost=num; g[a].push_back(e); } for(int i=1;i<=n;i++){ dijkstra(i); for(int j=1;j<=n;j++) dp[i][j]=d[j]; } int cnt; int mx=0; for(int i=1;i<=n;i++){ cnt=0; cnt+=dp[i][x]; cnt+=dp[x][i]; mx=max(cnt,mx); } cout<<mx<<endl; } return 0; } Followed by: Post your reply here: |
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