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0MS 利用二维数组的一点小转换 很简洁 附代码#include<iostream>
#include<string>
using namespace std;
int main()
{
int c;
while (cin >> c&&c != 0)
{
string str;
char a[100][100];
cin >> str;
int m = 0;
for (int i = 0; i <str.length()/c; i++)
{
for (int j = 0; j < c; j++)
{
a[i][j] = str[m];
m++;
}
}
for (int k = 0; k < c; k++)
{
for (int d = 0; d < str.length()/c; d++)
{
if (d % 2 == 0)
cout << a[d][k];
else
cout << a[d][c-1 - k];
}
}
cout << endl;
}
return 0;
}
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