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贴个单调队列优化的简洁高效模板~16ms#include <cstdio> #include <cstring> const int maxN=100005; int cash,n,a[15],w[15]; bool dp[maxN],q[maxN]; void zero_one_package(int i){for (int j = cash; j >= w[i]; j--) dp[j]=dp[j]||dp[j-w[i]];} void complete_package(int i){for (int j = w[i]; j <= cash; j++) dp[j]=dp[j]||dp[j-w[i]];} void multiple_package(int i) { for (int r = 0; r < w[i]; r++) { int front=0,rear=0,sum=0; for (int j = r; j <= cash; j+=w[i]) { q[rear++]=dp[j]; sum+=dp[j]; if (rear-front>a[i]+1) sum-=q[front++]; dp[j]=dp[j]||sum; } } } int solve() { for (int i = 1; i <= n; i++) { if (a[i]==1) zero_one_package(i); else if ((a[i]+1)*w[i]>cash) complete_package(i); else multiple_package(i); } for (int i = cash; i >= 0; i--) if (dp[i]) return i; } int main() { // freopen("D:\\input.txt","r",stdin); while (~scanf("%d%d",&cash,&n)) { for (int i = 1; i <= n; i++) scanf("%d%d",a+i,w+i); memset(dp,0,cash+1); dp[0]=true; printf("%d\n",solve()); } return 0; }//ac 16ms Followed by: Post your reply here: |
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