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生无可恋脸#include <iostream>
#include <stdio.h>
#include <algorithm>
#include <string.h>
using namespace std;
const int MAXN=110;
const int INF=0x3f3f3f3f;
bool vis[MAXN];
int lowc[MAXN];
int pre[MAXN];
int Max[MAXN][MAXN];
bool used[MAXN][MAXN];
int Prim(int cost[][MAXN],int n)
{
int ans=0;
memset(vis,false,sizeof(vis));
memset(Max,0,sizeof(Max));
memset(used,false,sizeof(used));
vis[0]=true;
pre[0]=-1;
for(int i=1;i<n;i++)
{
lowc[i]=cost[0][i];
pre[i]=0;
}
lowc[0]=0;
for(int i=1;i<n;i++)
{
int minc=INF;
int p=-1;
for(int j=0;j<n;j++)
if(!vis[j]&&minc>lowc[j])
{
minc=lowc[j];
p=j;
}
if(minc==INF)return -1;
ans+=minc;
vis[p]=true;
used[p][pre[p]]=used[pre[p]][p]=true;
for(int j=0;j<n;j++)
{
if(vis[j])Max[j][p]=Max[p][j]=max(Max[j][pre[p]],lowc[p]);
if(!vis[j]&&lowc[j]>cost[p][j])
{
lowc[j]=cost[p][j];
pre[j]=p;
}
}
}
return ans;
}
int ans;
int smst(int cost[][MAXN],int n)
{
int Min=INF;
for(int i=0;i<n;i++)
for(int j=i+1;j<n;j++)
if(cost[i][j]!=INF && !used[i][j])
{
Min=min(Min,ans+cost[i][j]-Max[i][j]);
}
if(Min==INF)return -1;
return Min;
}
int cost[MAXN][MAXN];
int main()
{
int T;
int n,m;
scanf("%d",&T);
while(T--)
{
scanf("%d%d",&n,&m);
int u,v,w;
for(int i=0;i<n;i++)
for(int j=0;j<n;j++)
{
if(i==j)cost[i][j]=0;
else cost[i][j]=INF;
}
while(m--)
{
scanf("%d%d%d",&u,&v,&w);
u--;v--;
cost[u][v]=cost[v][u]=w;
}
ans=Prim(cost,n);
if(ans==-1)
{
printf("Not Unique!\n");
continue;
}
if(ans==smst(cost,n))printf("Not Unique!\n");
else printf("%d\n",ans);
}
return 0;
}
/*
1
5 6
2 1 585
3 2 599
4 3 208
5 2 599
5 3 108
5 4 27
正确答案: Not Unique!
这段代码的答案: 1319
然后这段代码AC了,我WA了 ←_←
*/
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