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我了个去,终于AC了#include <iostream>
using namespace std;
int prime[12000],f[12000];
int tot;
int get_prime()
{
f[1]=1;
int i,j;
for(i=2; i<=11000; i++)
{
if(f[i]==0)
{
for(j=2; j<=11000/i; j++)
{
f[i*j]=1;
}
}
}
for(i=1,tot=0; i<=11000; i++)
{
if(f[i]==0)
prime[++tot]=i;
}
return 0;
}
bool is_prime(int num)
{
int i;
if(num==2)
return true;
for(i=1; i<=tot; i++)
{
if(prime[i]*prime[i]>num)
return true;
else if(num%prime[i]==0)
return false;
}
}
int digit(int num)
{
int sum=0;
while(num)
{
sum+=num%10;
num/=10;
}
return sum;
}
int main()
{
int k,i,j,t,sum_1,sum_2;
get_prime();
while(cin>>k&&k!=0)
{
for(i=k+1;; i++)
{
t=i;
sum_1=0;
sum_2=digit(t);
if(is_prime(t))
continue;
for(j=1; j<=tot&&t!=1; j++)
{
if(t%prime[j]==0)
{
sum_1+=digit(prime[j]);
t/=prime[j];
j--;
}
}
if(t!=1)
sum_1+=digit(t);
if(sum_2==sum_1)
{
cout<<i<<endl;
break;
}
}
}
return 0;
}
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