#include<stdio.h>

int main()
{
    int n;
    int a,b;
    scanf("%d",&n);
    while(n--)
    {
        scanf("%d:%d",&a,&b);

        if(b!=0){
            printf("0\n");
            continue;
        }

        printf("%d\n",(a+11)%24+1);
    }
    return 0;
}

• Re:很简单的代码 一次A (324) nextyoujie 2016-01-21 15:56:25