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Re:最少的盘子放了两个怎么办

Posted by 529127 at 2015-09-22 10:26:41 on Problem 1664
In Reply To:本题是很简单的递推 Posted by:libojie at 2009-02-20 00:09:06
> 本题是很简单的递推。
> ①最少的盘子放了一个,这样每个盘子至少一个,n个盘子先放上n个,剩下的m-n个可以随便放
> ②最少的盘子没有放,这样剩下的n-1个盘子还是随便放m个
> int f(int m,int n)
> { if(m<0)
>    return 0;
>   if(m==0||n==1)
>    return 1;
>   return f(m-n,n)+f(m,n-1);
> }

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