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直接上代码吧!哇咔咔。/*********************************************************************** Copyright (c) 2015,wangzp All rights no reserved. Name: 《Crazy tea party》In PEKING UNIVERSITY ACM ID: PROBLEM 1455 问题简述: N个人围成一圈,找出最快反着做需要调换座位的次数。 Date: SEP 09, 2015 ***********************************************************************/ #include <stdio.h> /*偶数个人*/ int fun_even(int n) { return n/2*(n/2 - 1); } /*奇数个人*/ int fun_odd(int n) { return (n/2)*(n/2 -1)/2 + (n/2 +1)*(n/2)/2; } int main(void) { int m,a,result; scanf("%d",&m); while(m--) { scanf("%d",&a); if (a%2 == 0) { result = fun_even(a); printf("%d\n",result); } else { result = fun_odd(a); printf("%d\n",result); } } return 0; } Followed by: Post your reply here: |
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