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G++ 用pair过不了为啥以下代码是用C++过的,用G++就是过不去 #include <cstdio> #include <cstring> #include <queue> #include <iostream> using namespace std; int vis[10][10]; int dir[8][2] = {{2,1},{2,-1},{-2,-1},{-2,1},{1,2},{1,-2},{-1,-2},{-1,2}}; int sx, sy, ex, ey; int BFS() { pair<int, int> st = make_pair(sx, sy); queue< pair<int, int> > Q; Q.push(st); vis[sx][sy] = 1; if(sx == ex && sy == ey) return 0; int x, y, t; int step = 0; while(!Q.empty()) { t = Q.size(); step++; while(t--) { st = Q.front(); Q.pop(); for(int i = 0; i < 8; i++) { x = st.first + dir[i][0]; y = st.second + dir[i][1]; if(x>=0&&x<8&&y>=0&&y<8&&!vis[x][y]) { vis[x][y] = 1; if(x == ex && y == ey) { return step; } Q.push(make_pair(x, y)); } } } } return 0; } int main() { char str1[5], str2[5]; while(scanf("%s%s", str1, str2) != EOF) { memset(vis, 0, sizeof(vis)); sx = str1[0] - 'a'; sy = str1[1] - '0' - 1; ex = str2[0] - 'a'; ey = str2[1] - '0' - 1; //cout << sx << sy << " " << ex << ey << endl; int step = BFS(); printf("To get from %s to %s takes %d knight moves.\n", str1, str2, step); } return 0; } Followed by: Post your reply here: |
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