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Re:四叉数TLE……orz。。。In Reply To:四叉数TLE……orz。。。 Posted by:dongshimou at 2015-02-24 18:12:44 #include<cstdio>
#include<cstring>
#include<cstdlib>
using namespace std;
int s[110000],ans,t,r[110000];
struct node
{
int x,y;
}k[110000];
int cmp(const void *x1,const void *x2)
{
node n1=*(node *)x1;
node n2=*(node *)x2;
if (n1.x!=n2.x) return n1.x-n2.x;
else return n1.y-n2.y;
}
int lowbit(int x)
{
return x & -x;
}
int qiuhe(int x)
{
int ans=0;
while(x>=1)
{
ans+=s[x];
x-=lowbit(x);
}
return ans;
}int n;
void gaibian(int x)
{
while(x<=n)
{
s[x]+=1;
x+=lowbit(x);
}
}
int main()
{
int t,m,i,kd;
while (scanf("%d",&n)!=EOF)
{
memset(s,0,sizeof(s));
if (n==0)break;
for (i=1;i<=n;i++)
{
scanf("%d",&r[i]);
k[i].x=r[i];
k[i].y=i;
}
qsort(k+1,n,sizeof(node ),cmp);
t=0;
kd=-99999;
for (i=1;i<=n;i++)
{
if (k[i].x>kd)
{
kd=k[i].x;
k[i].x=++t;
r[k[i].y]=k[i].x;
}
else
{
k[i].x=t;
r[k[i].y]=k[i].x;
}
}
ans=0;
for (i=1;i<=n;i++)
{
gaibian(r[i]);
ans+=i-qiuhe(r[i]);
}
printf("%d\n",ans);
}
return 0;
}
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