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Re:四叉数TLE……orz。。。

Posted by 1339097071 at 2015-08-23 11:42:53 on Problem 2155
In Reply To:四叉数TLE……orz。。。 Posted by:dongshimou at 2015-02-24 18:12:44
#include<cstdio>
#include<cstring>
#include<cstdlib>
using namespace std;
int s[110000],ans,t,r[110000];
struct node
{
	int x,y;
}k[110000];
int cmp(const void *x1,const void *x2)
{
	node n1=*(node *)x1;
	node n2=*(node *)x2;
	if (n1.x!=n2.x) return n1.x-n2.x;
	else return n1.y-n2.y;
}

int lowbit(int x) 
{
    return x & -x;
}

int qiuhe(int x)
{
    int ans=0;
    while(x>=1)
	{
        ans+=s[x];
        x-=lowbit(x);
    }
    return ans;
}int n;
void gaibian(int x)
{
    while(x<=n)
	{
        s[x]+=1;
        x+=lowbit(x);
    }
}

int main()
{
	int t,m,i,kd;
	while (scanf("%d",&n)!=EOF)
	{
		memset(s,0,sizeof(s));
		if (n==0)break;
		for (i=1;i<=n;i++)
		{
			scanf("%d",&r[i]);
			k[i].x=r[i];
			k[i].y=i;
		}
		qsort(k+1,n,sizeof(node ),cmp);
		t=0;
		kd=-99999;
		for (i=1;i<=n;i++)
		{
			if (k[i].x>kd)
			{
				kd=k[i].x;
				k[i].x=++t;
				r[k[i].y]=k[i].x;
			}
			else
			{
				k[i].x=t;
				r[k[i].y]=k[i].x;
			}
		}
		
		ans=0;
		for (i=1;i<=n;i++)
		{
			gaibian(r[i]);
			ans+=i-qiuhe(r[i]);
		}
		printf("%d\n",ans);
	} 
	return 0;
}

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