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求负权的单源最短路是不是等于求正权的单源最长路?我的代码WA了-_-||In Reply To:这题用差分约束系统分析之后,是不是就是求单源最长路? Posted by:animate at 2005-10-19 15:13:50 #include<cstdio>
#include<iostream>
using namespace std;
int n,m,s;
int E[100200][3];
int D[50100];
void BellmanFord(){
int i,j,k;
for(i=s;i<=m;i++)D[i]=1;
D[s]=0;
for(k=1;k<=m;k++){
for(j=0;j<n;j++){
int u=E[j][0],v=E[j][1],e=E[j][2];
if(D[u]!=1&&D[v]>D[u]+e){
D[v]=D[u]+e;
}
}
}
printf("%d\n",-D[m]);
}
int main(){
//freopen("in.txt","r",stdin);
scanf("%d",&n);
int i;
int u,v,e;
m=-1;s=-1;
for(i=0;i<n;i++){
scanf("%d%d%d",&u,&v,&e);
E[i][0]=u;
if(s==-1||s>u)s=u;
E[i][1]=v+1;
if(v+1>m)m=v+1;
E[i][2]=-e;
}
for(i=s;i<m;i++){
E[n][0]=i;
E[n][1]=i+1;
E[n][2]=0;
n++;
}
BellmanFord();
}
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