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求负权的单源最短路是不是等于求正权的单源最长路?我的代码WA了-_-||In Reply To:这题用差分约束系统分析之后,是不是就是求单源最长路? Posted by:animate at 2005-10-19 15:13:50 #include<cstdio> #include<iostream> using namespace std; int n,m,s; int E[100200][3]; int D[50100]; void BellmanFord(){ int i,j,k; for(i=s;i<=m;i++)D[i]=1; D[s]=0; for(k=1;k<=m;k++){ for(j=0;j<n;j++){ int u=E[j][0],v=E[j][1],e=E[j][2]; if(D[u]!=1&&D[v]>D[u]+e){ D[v]=D[u]+e; } } } printf("%d\n",-D[m]); } int main(){ //freopen("in.txt","r",stdin); scanf("%d",&n); int i; int u,v,e; m=-1;s=-1; for(i=0;i<n;i++){ scanf("%d%d%d",&u,&v,&e); E[i][0]=u; if(s==-1||s>u)s=u; E[i][1]=v+1; if(v+1>m)m=v+1; E[i][2]=-e; } for(i=s;i<m;i++){ E[n][0]=i; E[n][1]=i+1; E[n][2]=0; n++; } BellmanFord(); } Followed by:
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