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一种思路,DP把线段按横坐标排序,每条线段映射成一个点,当a[x].end<=a[y].start时,表示x可以连接到y。
dp[i]表示从第i个点往后最多可连接的点的数目(包括该点)
way[i]表示从第i个点往后最多可连接的点的数目最大时的连接方案数
代码
#include <stdio.h>
#include <algorithm>
using namespace std;
struct node{
int x,y;
} a[100];
int dp[200],way[200];
bool d[100][100];
bool cmp(node a,node b)
{
if (a.x!=b.x) return a.x<b.x;
else
return a.y<b.y;
}
int main()
{
int n,ans,max;
while (scanf("%d",&n)!=EOF)
{
ans=0;max=-1;
for (int i=0;i<n;i++)
for (int j=0;j<n;j++)
d[i][j]=false;
for (int i=0;i<n;i++)
{
dp[i]=0;
way[i]=0;
}
for (int i=0;i<n;i++)
{
scanf("%d%d",&a[i].x,&a[i].y);
if (a[i].x>a[i].y)
{
int temp=a[i].x;
a[i].x=a[i].y;
a[i].y=temp;
}
}
sort(a,a+n,cmp);
for (int i=0;i<n;i++)
for (int j=i+1;j<n;j++)
if (a[i].y<=a[j].x)
d[i][j]=true;
for (int i=n-1;i>=0;i--)
{
for (int j=i+1;j<n;j++)
if (d[i][j])
{
if (dp[i]<dp[j]+1)
{
dp[i]=dp[j]+1;
way[i]=way[j];
}
else
if (dp[i]==dp[j]+1)
{
way[i]+=way[j];
}
}
if (dp[i]==0)
{
dp[i]=1;
way[i]=1;
}
if (max<dp[i])
{
max=dp[i];
ans=way[i];
}
else
if (max==dp[i])
{
ans+=way[i];
}
}
printf("%d %d\n",n-max,ans);
}
return 0;
}
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