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1006题所有的用例都通过了,讨论里的也可以通过,为什么提示wrong answer,附代码#include <iostream> #define CONTINUEINPUT(p, e, i, d) ((-1 == p) && (-1 == e) && (-1 == i) && (-1 == d)) #define VALIDINPUT(p, e, i, d) ((0 <= p) && (0 <= e) && (0 <= i) && (0 <= d) \ && (365 > p) && (365 > e) && (365 > i) && (365 > d)) #define PERIOD_PHYSICAL 23 #define PERIOD_EMOTIONAL 28 #define PERIOD_INTELLECTUAL 33 #define PERIOD_TRIPLE_PEAK (23 * 28 * 33) using namespace std; int main() { int p = 0; int e = 0; int i = 0; int d = 0; int case_cnt = 0; // case count for (cin >> p >> e >> i >> d; ! CONTINUEINPUT(p, e, i, d); cin >> p >> e >> i >> d) { if (! VALIDINPUT(p, e, i, d)) { continue; } ++case_cnt; // increase one by one loop int physical = p % PERIOD_PHYSICAL; int emotional = e % PERIOD_EMOTIONAL; int intellectual = i % PERIOD_INTELLECTUAL; for (int TriplePeak = intellectual; TriplePeak < d + PERIOD_TRIPLE_PEAK; TriplePeak += PERIOD_INTELLECTUAL) { if ( 0 == ((TriplePeak - emotional) % PERIOD_EMOTIONAL) && 0 == ((TriplePeak - physical) % PERIOD_PHYSICAL)) { int future = 0; if (TriplePeak <= d) { TriplePeak += PERIOD_TRIPLE_PEAK; } future = TriplePeak - d; cout << "Case " << case_cnt <<": the next triple peak occurs in " << future << " days." << endl; break; } } } return 0; } Followed by: Post your reply here: |
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