| ||||||||||
| Online Judge | Problem Set | Authors | Online Contests | User | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest | |||||||||
终于过了。。。此题的关键是while(cin.eof) 不能写成while(true),否则OLE。另外最好边输入边输出#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
int n;
cin>>n;
while (cin.eof())
{
long double *x = new long double[n];
long double *y = new long double[n];
cout<<n<<" ";
cin>>x[0]>>y[0];
for (int i = 1; i < n; i++)
{
cin>>x[i]>>y[i];
cout<<fixed<<setprecision(6)<<(x[i-1]+x[i]) / 2.0<<" "<<(y[i-1]+y[i]) / 2.0<<" ";
}
cout<<fixed<<setprecision(6)<<(x[0]+x[n-1]) / 2.0<<" "<<(y[0] + y[n-1]) / 2.0<<endl;
cin>>n;
}
return 0;
}
Followed by: Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator