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数据太弱了。这样的程序也能A(有数据为证,明显not unique)/*********数据*****/
1
4 4
1 2 3
2 3 1
3 4 3
4 1 1
/*********数据*****/
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cstdlib>
using namespace std;
#define N 105
#define INF 99999999
int map[N][N];
int dis[N];
int visit[N];
int n;
void prim()
{
int i,j,v,min,k,flag,sum;
for(i=1;i<=n;i++)
dis[i]=map[1][i];
flag=0;
sum=0;
memset(visit,0,sizeof(visit));
for(i=1;i<=n;i++)
{
min=INF;
for(j=1;j<=n;j++)
if(!visit[j]&&dis[j]<min)
{
min=dis[j];
v=j;
}
k=0;
for(j=1;j<=n;j++)
if(visit[j]&&map[v][j]==min)
k++;
if(k>1)
{
flag=1;
break;
}
visit[v]=1;
sum+=min;
for(j=1;j<=n;j++)
if(!visit[j]&&dis[j]>map[v][j])
dis[j]=map[v][j];
}
if(flag)
printf("Not Unique!\n");
else
printf("%d\n",sum);
}
int main()
{
int t;
int i,j,m;
int a,b,c;
scanf("%d",&t);
while(t--)
{
scanf("%d%d",&n,&m);
for(i=1;i<=n;i++)
for(j=1;j<=n;j++)
{
map[i][j]=INF;
if(i==j)
map[i][j]=0;
}
while(m--)
{
scanf("%d%d%d",&a,&b,&c);
if(map[a][b]>c)
{
map[a][b]=map[b][a]=c;
}
}
prim();
}
return 0;
}
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