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可以找出所有必败点。void run() { int n = in.nextInt(); int[] is = { 0, 6, 12, 22, 30, 32, 44, 54, 64, 76, 86, 98, 110, 118, 130, 132, 162, 170, 184, 194, 202, 282, 290, 302, 356, 1046 }; for (int i : is) if (i == n) { out.println(2); return ; } out.println(1); } Followed by: Post your reply here: |
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