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输出No duplicates.的时候,用cout可以,用printf就报错为什么呢?

Posted by soap_ at 2014-08-13 11:31:38 on Problem 1002
#include<iostream>  
#include<algorithm>  
#include<string.h>
using namespace std; 
int convert(char ch)
{  
    if(ch=='A' || ch=='B' || ch=='C')  
        return 2;  
    if(ch=='D' || ch=='E' || ch=='F')  
        return 3;  
    if(ch=='G' || ch=='H' || ch=='I')  
        return 4;  
    if(ch=='J' || ch=='K' || ch=='L')  
        return 5;  
    if(ch=='M' || ch=='N' || ch=='O')  
        return 6;  
    if(ch=='P' || ch=='R' || ch=='S')  
        return 7;  
    if(ch=='T' || ch=='U' || ch=='V')  
        return 8;  
    if(ch=='W' || ch=='X' || ch=='Y')  
        return 9;  
}  
int time[10000000];
bool is[10000000];
int num[100000]; 
int main()
{
	int n;
	while(cin>>n)
	{		
		memset(time,0,sizeof(time));
		memset(is,false,sizeof(is));
		int ps=0;
		bool flag=false;
		for(int i=0;i<n;i++)
		{
			int x=0;
			char s[20];
			cin>>s; 
			for(int j=0;s[j]!='\0';j++)
			{
				if(s[j]=='-' || s[j]=='Q' || s[j]=='Z')  
                    continue;  
                else if(s[j]<='9')  
                    x=x*10+s[j]-'0';  
                else if(s[j]<='Z')  
                    x=x*10+convert(s[j]);
			}
			time[x]++;
		  	if(!is[x] && time[x]>=2) 
            {  
                flag=true;  
                is[x]=true;  
                num[ps++]=x;  
            }  
		}
		if(!flag)
//			cout<<"No duplicates."<<endl;
			printf("No duplicates.\n");
		else
		{
			sort(num,num+ps);  
            for(int i=0;i<ps;i++)              
            	printf("%03d-%04d %d\n",num[i]/10000,num[i]%10000,time[num[i]]);            
		}
	}	 
	return 0;
}



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