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求管理员或者大神解答--求帮助,两份ac代码,却对于这两组测试数据输出不同的结果,到底哪个是对的? 数据: 100 8 32 18 17 44 25 65 6 58 3 3 4 7 1 6 7 2 4 1 6 7 2 1 2 7 6 3 2 3 1 4 2 4 5 1 1 3 1 5 7 3 4 5 7 4 5 2 1 1 2 7 3 3 7 1 1 7 2 7 3 5 5 2 6 3 3 7 6 2 7 3 2 8 1 11 132 21 46 84 66 97 34 91 33 90 40 84 2 9 11 10 2 8 3 10 7 7 5 1 4 3 9 6 2 3 9 10 6 7 1 7 9 4 11 1 4 10 2 8 4 2 10 10 7 11 7 2 11 7 1 8 2 4 8 9 8 2 1 11 5 9 2 3 8 8 5 1 5 10 3 6 11 2 7 6 10 10 9 1 11 8 7 1 5 1 7 2 7 5 7 3 7 7 3 8 4 7 11 4 2 11 2 8 10 6 9 10 3 10 6 11 11 11 9 2 7 2 9 9 6 4 2 6 10 1 9 11 9 2 9 4 8 7 1 6 7 4 11 9 3 2 5 5 3 8 2 11 11 11 7 4 9 2 8 4 7 1 11 2 5 6 6 3 8 5 2 7 8 1 10 6 10 1 5 1 8 9 5 8 6 10 8 2 9 11 10 11 10 4 10 4 8 7 1 8 2 11 3 3 11 4 9 10 1 1 1 6 11 1 11 4 10 10 5 8 6 9 7 11 9 8 10 8 6 3 11 8 11 7 7 5 7 4 6 7 11 5 11 8 6 4 5 5 6 3 8 11 6 2 5 7 9 6 11 7 6 9 3 4 6 4 2 7 9 4 2 7 2 5 10 5 第一份代码输出: 79469 1 3434406 1 第二份代码输出: 555392 72 4650271 600 第一份代码(别人的): #include <stdio.h> #include <string.h> typedef __int64 i64; const int maxn = 13; const int maxs = 1<<maxn | 1; i64 dp[maxn][maxn][maxs], way[maxn][maxn][maxs]; int map[maxn][maxn], v[maxn]; int n, m, S; void StateCompressDp() { memset(dp, -1, sizeof(dp)); memset(way, 0, sizeof(way)); for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { if (map[i][j]) { dp[i][j][(1<<i)+(1<<j)] = v[i] + v[j] + v[i]*v[j]; way[i][j][(1<<i)+(1<<j)] = 1; } } } for (int p = 3; p < S; p++) { for (int i = 0; i < n; i++) { if (!(p&1<<i)) continue; for (int j = 0; j < n; j++) { if (i == j || !(p&1<<j) || dp[i][j][p] == -1) continue; for (int k = 0; k < n; k++) { if (p&1<<k || !map[j][k]) continue; int r = p + (1 << k); i64 q = dp[i][j][p] + v[k] + v[j]*v[k]; if (map[i][k]) { q += v[i] * v[j] * v[k]; } if (q > dp[j][k][r]) { dp[j][k][r] = q; way[j][k][r] = way[i][j][p]; } else if (q == dp[j][k][r]) { way[j][k][r] += way[i][j][p]; } } } } } return ; } int main () { int t; scanf("%d", &t); while (t--) { int tmpx, tmpy; memset(map, 0, sizeof(map)); scanf("%d%d", &n, &m); for (int i = 0; i < n; i++) { scanf("%d", &v[i]); } for (int i = 0; i < m; i++) { scanf("%d%d", &tmpx, &tmpy); map[tmpx-1][tmpy-1] = map[tmpy-1][tmpx-1] = 1; } S = 1 << n; if (n == 1) { printf("%d %d\n", v[0], 1); } else { StateCompressDp(); i64 ansv = -1, ansp = 0; for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { if (i == j) continue; if (dp[i][j][S-1] > ansv) { ansv = dp[i][j][S-1]; ansp = way[i][j][S-1]; } else if (dp[i][j][S-1] == ansv) { ansp += way[i][j][S-1]; } } } printf("%I64d %I64d\n", ansv == -1 ? 0 : ansv, ansp/2); } } return 0; } 第二份代码(本人的): #include<iostream> #include<cstdio> #include<cstring> #include<vector> #include<queue> using namespace std; typedef __int64 ss; const ss inf=(1<<14); bool map[20][20],vist[14][14][inf]; ss dp[14][14][inf],n,m,s[20],path[14][14][inf]; vector<ss>vet[20]; struct node { ss num,pre,zt; }; queue<node>q; void spfa() { if(!q.empty()) q.pop(); for(int i=0;i<n;i++) { for(int j=0;j<n;j++) { if(map[i][j]) { int tmp=(1<<i)+(1<<j); if(dp[i][j][tmp]<s[i]+s[j]+s[i]*s[j]) { dp[i][j][tmp]=s[i]+s[j]+s[i]*s[j]; path[i][j][tmp]=1; if(!vist[i][j][tmp]) { vist[i][j][tmp]=true; node p; p.num=j; p.pre=i; p.zt=tmp; q.push(p); } } } } } while(!q.empty()) { //printf("111\n"); node p=q.front(); q.pop(); vist[p.num][p.pre][p.zt]=false; for(ss j=0;j<vet[p.num].size();j++) { ss i=vet[p.num][j]; //printf("%I64d %I64d\n",p.num,i); if(p.zt&(1<<i)) continue; //if(i==p.num) continue; //if(!map[p.num][i]) continue; node p1; p1.zt=p.zt|(1<<i); p1.num=i; p1.pre=p.num; ss ans=0; ans+=dp[p.num][p.pre][p.zt]+s[i]+s[i]*s[p.num]; ss tmp=p.pre; if(map[i][tmp]) { ans+=s[tmp]*s[i]*s[p.num]; } if(ans>dp[p1.num][p1.pre][p1.zt]) { dp[p1.num][p1.pre][p1.zt]=ans; path[p1.num][p1.pre][p1.zt]=path[p.num][p.pre][p.zt]; if(!vist[p1.num][p1.pre][p1.zt]) q.push(p1); vist[p1.num][p1.pre][p1.zt]=true; } else if(ans==dp[p1.num][p1.pre][p1.zt]) path[p1.num][p1.pre][p1.zt]+=path[p.num][p.pre][p.zt]; } } } int main() { int text; scanf("%d",&text); while(text--) { scanf("%I64d%I64d",&n,&m); memset(dp,-1,sizeof(dp)); memset(map,false,sizeof(map)); memset(vist,false,sizeof(vist)); memset(path,0,sizeof(path)); for(ss i=0;i<=n;i++) vet[i].clear(); for(ss i=0;i<n;i++) scanf("%I64d",&s[i]); for(ss i=1;i<=m;i++) { ss a,b; scanf("%I64d%I64d",&a,&b); a--; b--; map[a][b]=map[b][a]=true; vet[a].push_back(b); vet[b].push_back(a); } if(n==1) { printf("%I64d 1\n",s[0]); continue; } spfa(); ss maxn=0,ans=(1<<(n))-1; ss tol=0; for(ss i=0;i<n;i++) { for(ss j=0;j<n;j++) { if(maxn<dp[i][j][ans]) { tol=path[i][j][ans]; maxn=dp[i][j][ans]; } else if(maxn==dp[i][j][ans]) { tol+=path[i][j][ans]; } } } if(maxn==0) printf("0 0\n"); else printf("%I64d %I64d\n",maxn,tol/2); } return 0; } Followed by: Post your reply here: |
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