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线段树+离散化+扫描线

Posted by ecjtu_yuweiwei at 2014-07-29 14:58:50 on Problem 1151
#include<iostream>
#include<queue>
#include<cstdio>
#include<algorithm>
#include<cstring>
#include<iomanip>
#include<map>
#include<cstdlib>
#include<cmath>
#include<vector>
#define LL long long
#define IT __int64
#define zero(x) fabs(x)<eps
#define mm(a,b) memset(a,b,sizeof(a))
const int INF=0x7fffffff;
const double inf=1e8;
const double eps=1e-10;
const double PI=acos(-1.0);
const int Max=201;
using namespace std;
int sign(double x)
{
    return (x>eps)-(x<-eps);
}
struct Node
{
    int left;
    int right;//线段树的左右整点
    int flag;//记录重叠情况,大于零说明没有重叠
    double cnt;//记录实际的长度
    double lf;//左边端点真实的浮点数
    double rf;//右边端点真是的浮点数
}segTree[Max<<2];
struct Line
{
    double x;
    double y1;
    double y2;
    int ok;
}line[Max];
double y[Max];//记录y坐标的数组
//把一段段平行于y轴的线段表示成数组
//x是线段的x坐标,y1,y2线段对应的下端点和上端点的坐标
//一个矩形 ,左边的那条边ok为1,右边的为-1
//用来记录重叠情况,可以根据node节点中的flag这个来计算
bool cmp(Line u,Line v)//sort排序
{
    return u.x<v.x;
}
void Build_Tree(int t,int left,int right)
{
    segTree[t].left=left;
    segTree[t].right=right;
    segTree[t].lf=y[left];
    segTree[t].rf=y[right];
    if((left+1)==right) return;
    int mid=(left+right)>>1;
    Build_Tree(t<<1,left,mid);
    Build_Tree(t<<1|1,mid,right);//递归构造线段树,这里mid不能+1因为如果+1那么t<<1的右孩子和t<<1|1的左孩子不能产生联系最终更新父节点就是错误的数据
}
void Calen(int t)//计算长度
{
    if(segTree[t].flag>0)//如果没有重叠
    {
        segTree[t].cnt=segTree[t].rf-segTree[t].lf;
    }
    else if(segTree[t].left+1==segTree[t].right)//如果重叠了
    {
        segTree[t].cnt=0;
    }
    else
    {
        segTree[t].cnt=segTree[t<<1].cnt+segTree[t<<1|1].cnt;
    }
}
void Update(int t,Line L)//加入线段L,后更新线段树
{
    if(L.y1==segTree[t].lf&&L.y2==segTree[t].rf)
    {
        segTree[t].flag+=L.ok;
        Calen(t);
    }
    else if(L.y2<=segTree[t<<1].rf)
    {
        Update(t<<1,L);
    }
    else if(L.y1>=segTree[t<<1|1].lf)
    {
        Update(t<<1|1,L);
    }
    else
    {
        Line temp;
        temp=L;
        temp.y2=segTree[t<<1].rf;
        Update(t<<1,temp);
        temp=L;
        temp.y1=segTree[t<<1|1].lf;
        Update(t<<1|1,temp);
    }
    Calen(t);
}
void Init(int &m,double x1,double y1,double x2,double y2)
{
    line[m].x=x1;
    line[m].y1=y1;
    line[m].y2=y2;
    line[m].ok=1;
    y[m]=y1;
    m++;
    line[m].x=x2;
    line[m].y1=y1;
    line[m].y2=y2;
    line[m].ok=-1;
    y[m]=y2;
    m++;
}
int main()
{
    int n,m,i,j,Case;
    double x1,y1,x2,y2,area;
    Case=1;
    while(cin>>n&&n)
    {
        m=1;
        for(i=1;i<=n;i++)
        {
            cin>>x1>>y1>>x2>>y2;
            Init(m,x1,y1,x2,y2);
        }
        sort(line+1,line+m,cmp);
        sort(y+1,y+m);
        Build_Tree(1,1,m-1);
        Update(1,line[1]);
        area=0;
        for(i=2;i<m;i++)
        {
            //cout<<segTree[1].cnt<<" "<<line[i-1].x<<" "<<line[i].x<<endl;
            area+=segTree[1].cnt*(line[i].x-line[i-1].x);
            Update(1,line[i]);
        }
        cout<<"Test case #"<<Case++<<endl;
        cout<<"Total explored area: "<<setprecision(2)<<setiosflags(ios::fixed)<<area<<endl<<endl;
    }
    return 0;
}

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