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Re:为什么会Runtime Error?In Reply To:为什么会Runtime Error? Posted by:shuangkouchengzhi at 2014-04-29 16:41:56 > #include <iostream>
> using namespace std;
> void check(char**p,int,int);
> int main()
> {
> int N,M;
> cin>>M>>N;
> char**p=new char*[N];
> for (int i=0;i<N;i++) p[i]=new char[M];
> for (int j=0;j<N+2;j++)
> {
> p[0][j]='.';
> p[M+1][j]='.';
> }
> for (int i=1;i<M+1;i++)
> {
> p[i][0]='.';
> p[i][N+1]='.';
> }
> for (int i=1;i<=M;i++)
> for (int j=1;j<=N;j++)
> cin>>p[i][j];
> int counter=0;
> for(int i=1;i<=M;i++)
> for(int j=1;j<=N;j++)
> if(p[i][j]=='W')
> {
> counter++;
> p[i][j]=1;
> check(p,i,j);
> }
> cout<<counter<<endl;
> for (int i=0;i<N;i++) delete[] p[i];
> delete[] p;
> return 0;
>
> }
>
> void check(char**p,int hang,int lie)
> {
> bool flag=true;
> while(flag)
> {
> flag=false;
> if (p[hang-1][lie+1]=='W')
> {
> flag=true;
> p[hang-1][lie+1]=1;
> check(p,hang-1,lie+1);
> }
> for(int i=hang;i<=hang+1;i++)
> for(int j=lie-1;j<=lie+1;j++)
> {
> if(p[i][j]=='W')
> {
> flag=true;
> p[i][j]=1;
> check(p,i,j);
> }
> }
> }
> if(flag==false) return;
>
> }
>
话说这题100字符而已,你动态分配不仅节约不了多少内存,反而代码量增加,何苦呢.而且即使要
动态分配,还是要多分配一点的...留点余地,这可以增强程序的鲁棒性.有些题目的数据可能是有缺陷的,比如要求100,但是它给了101,,要是你不知情,怎么破?
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