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有个定理,用了就很简单的。

Posted by 913106840245 at 2014-07-16 08:37:20 on Problem 3219
#include <iostream>
using namespace std;
int main ()
{
	int n,k;
	while(cin>>n>>k)
		cout<<(((n-k)&k)>0?0:1)<<endl;
return 0;
}

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