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Re:真是找不到问题 测试数据全过了 跪求指导 谢谢了In Reply To:真是找不到问题 测试数据全过了 跪求指导 谢谢了 Posted by:VJing at 2014-04-13 16:01:53 > #include<stdio.h>
> #include<stdlib.h>
>
> //排序
> int Compare(const void *elem1, const void *elem2)
> {
> return *((int *)(elem1)) - *((int *)(elem2));
> }
>
> int main()
> {
> int count, temp, i, j, n, number, flag = 0;
> int array[100001];
> char str[500];
> for(i = 0; i <= 100000; i++)
> array[i] = -1;
> scanf("%d", &count);
>
> //处理数据,全部转为整形
> for(i = 0; i < count; i++)
> {
> array[i] = 0;
> temp = 1000000;
> scanf("%s", str);
> for(j = 0; str[j] != NULL;j++)
> {
> if(str[j] != '-' && str[j] != 'Q' && str[j] != 'Z')
> {
> if(str[j] == '1')
> array[i] += 1 * temp;
> if(str[j] == 'A' || str[j] == 'B' || str[j] == 'C' || str[j] == '2')
> array[i] += 2 * temp;
> if(str[j] == 'D' || str[j] == 'E' || str[j] == 'F' || str[j] == '3')
> array[i] += 3 * temp;
> if(str[j] == 'G' || str[j] == 'H' || str[j] == 'I' || str[j] == '4')
> array[i] += 4 * temp;
> if(str[j] == 'J' || str[j] == 'K' || str[j] == 'L' || str[j] == '5')
> array[i] += 5 * temp;
> if(str[j] == 'M' || str[j] == 'N' || str[j] == 'O' || str[j] == '6')
> array[i] += 6 * temp;
> if(str[j] == 'P' || str[j] == 'R' || str[j] == 'S' || str[j] == '7')
> array[i] += 7 * temp;
> if(str[j] == 'T' || str[j] == 'U' || str[j] == 'V' || str[j] == '8')
> array[i] += 8 * temp;
> if(str[j] == 'W' || str[j] == 'X' || str[j] == 'Y' || str[j] == '9')
> array[i] += 9 * temp;
>
> temp /= 10;//从高位到地位,每次位权都要减小
> }
> }
> }
>
> //排序
> qsort(array, count, sizeof(int), Compare);
>
> //输出
> number = array[0];
> n = 0;
> for(i = 0; i <= count; i++)
> {
> if(number != array[i])
> {
> if(n > 1)
> {
> if(array[i - 1] % 10000 == 0 && array[i - 1] / 10000 == 0)
> printf("000-0000 %d\n",n);
> else if(array[i - 1] % 10000 == 0)
> printf("%3d-0000 %d\n", array[i - 1] / 10000, n);
> else if(array[i - 1] / 10000 == 0)
> printf("000-%4d %d\n", array[i - 1] % 10000, n);
>
> else
> printf("%3d-%4d %d\n",array[i - 1] / 10000, array[i - 1] % 10000, n);
> flag = 1;
> }
> n = 1;
> number = array[i];
> }
> else
> {
> n++;
> }
> }
>
> //如果没有,输出No duplicates.
> if(flag == 0)
> printf("No duplicates.\n");
> return 0;
> }
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