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真是找不到问题 测试数据全过了 跪求指导 谢谢了

Posted by VJing at 2014-04-13 16:01:53 on Problem 1002
#include<stdio.h>
#include<stdlib.h>

//排序
int Compare(const void *elem1, const void *elem2)
{
    return *((int *)(elem1)) - *((int *)(elem2));
}

int main()
{
	int count, temp, i, j, n, number, flag = 0;
	int array[100001];
	char str[500];
	for(i = 0; i <= 100000; i++)
		array[i] = -1;
	scanf("%d", &count);

	//处理数据,全部转为整形
	for(i = 0; i < count; i++)
	{
		array[i] = 0;
		temp = 1000000;
		scanf("%s", str);
		for(j = 0; str[j] != NULL;j++)
		{
			if(str[j] != '-' && str[j] != 'Q' && str[j] != 'Z')
			{
				if(str[j] == '1')
					array[i] += 1 * temp;
				if(str[j] == 'A' || str[j] == 'B' || str[j] == 'C' || str[j] == '2')
					array[i] += 2 * temp;
				if(str[j] == 'D' || str[j] == 'E' || str[j] == 'F' || str[j] == '3')
					array[i] += 3 * temp;
				if(str[j] == 'G' || str[j] == 'H' || str[j] == 'I' || str[j] == '4')
					array[i] += 4 * temp;
				if(str[j] == 'J' || str[j] == 'K' || str[j] == 'L' || str[j] == '5')
					array[i] += 5 * temp;
				if(str[j] == 'M' || str[j] == 'N' || str[j] == 'O' || str[j] == '6')
					array[i] += 6 * temp;
				if(str[j] == 'P' || str[j] == 'R' || str[j] == 'S' || str[j] == '7')
					array[i] += 7 * temp;
				if(str[j] == 'T' || str[j] == 'U' || str[j] == 'V' || str[j] == '8')
					array[i] += 8 * temp;
				if(str[j] == 'W' || str[j] == 'X' || str[j] == 'Y' || str[j] == '9')
					array[i] += 9 * temp;

				temp /= 10;//从高位到地位,每次位权都要减小
			}
		}
	}
	
	//排序
	qsort(array, count, sizeof(int), Compare);

	//输出
	number = array[0];
	n = 0;
	for(i = 0; i <= count; i++)
	{
		if(number != array[i])
		{
			if(n > 1)
			{
				if(array[i - 1] % 10000 == 0 && array[i - 1] / 10000 == 0)
					printf("000-0000 %d\n",n);
				else if(array[i - 1] % 10000 == 0)
					printf("%3d-0000 %d\n", array[i - 1] / 10000, n);
				else if(array[i - 1] / 10000 == 0)
					printf("000-%4d %d\n", array[i - 1] % 10000, n);
					
				else
					printf("%3d-%4d %d\n",array[i - 1] / 10000, array[i - 1] % 10000, n);
				flag = 1;
			}
			n = 1;
			number = array[i];
		}
		else
		{
			n++;
		}
	}

	//如果没有,输出No duplicates.
	if(flag == 0)
		printf("No duplicates.\n");
	return 0;
}

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