Online JudgeProblem SetAuthorsOnline ContestsUser
Web Board
Home Page
F.A.Qs
Statistical Charts
Problems
Submit Problem
Online Status
Prob.ID:
Register
Update your info
Authors ranklist
Current Contest
Past Contests
Scheduled Contests
Award Contest
User ID:
Password:
  Register

终于过了 贴个AC代码

Posted by 09876543210 at 2014-03-13 17:40:45 on Problem 1328
#include<iostream>
#include<algorithm>
#include<cmath>
using namespace std;
struct point
{
	double x1,x2;
}p[1005];
bool cmp(point a,point b)
{
	return a.x1<b.x1;
}
int main()
{
	int n,r,i,t,end_flag,count;
	double temp,x,y;
	t=1;
	while(cin>>n>>r)
	{
		if(n==0&&r==0) break;
		end_flag=0;
		count=1;
		for(i=1;i<=n;i++)
		{
			cin>>x>>y;
			if(y>r) end_flag=1;
			p[i].x1=x-sqrt(r*r-y*y);
			p[i].x2=x+sqrt(r*r-y*y);
		}
		cout<<"Case "<<t++<<": ";
		if(end_flag)
		{
			cout<<-1<<endl;
			continue;
		}
		sort(p+1,p+n+1,cmp);
		temp=p[1].x2;
		for(i=2;i<=n;i++)
		{
			if(p[i].x2<temp) temp=p[i].x2;//如果下一个区间在当前区间的内部。
			else if(p[i].x1>temp)//如果下一个区间不在当前区间内。
			{
				count++;
				temp=p[i].x2;
			}
			//不考虑两个区间有交集,此时雷达还是限制在原区间右端点。就这儿错了啊啊啊!!!
		}
		cout<<count<<endl;
	}
	return 0;
}

Followed by:

Post your reply here:
User ID:
Password:
Title:

Content:

Home Page   Go Back  To top


All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator