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提供两组数据都说是求割点,其实感觉是求块
两组数据构成的图是一样的,只是插入边的顺序不一样
5
1 3 2
2 4 5 3
4 5
0
5
1 2 3
2 3 4 5
4 5
0
都输出:1
void tarjan(int u,int father){
dfn[u]=low[u]=++index;
for(int i=head[u];i != -1;i=edge[i].next){
int v=edge[i].v;
if(v == father)continue;
if(!dfn[v]){
tarjan(v,u);
if(low[v]>=dfn[u])++sum[u];
low[u]=min(low[u],low[v]);
}else low[u]=min(low[u],dfn[v]);
//low[u]=min(low[u],low[v]);
}
}
注意else 的时候一定要是low[u]=min(low[u],dfn[v]);而不是low[u]=min(low[u],low[v]);
想一下就知道了,其实求块要分if else也是这个原因
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