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Re:一个简单的代码In Reply To:一个简单的代码 Posted by:fuliang at 2009-05-03 23:46:19 > #include<iostream>
> #include<cstring>
> #include<cmath>
> using namespace std;
>
> int dif[3000];
>
> int main(){
> int n;
> while(cin >> n){
> memset(dif,0,sizeof(dif));
> int pre,current;
> cin >> pre;
> int i;
> for(i = 1; i < n; i++){
> cin >> current;
> int abs_dif = abs(current - pre);
> dif[abs_dif] = 1;
> pre = current;
> }
>
> for(i = 1; i < n; i++){
> if(dif[i] == 0)
> break;
> }
>
> if(i == n)
> cout << "Jolly" << endl;
> else
> cout << "Not jolly" << endl;
> }
> }
当n=1的时候不是没有结果么
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