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数组#include <iostream> using namespace std; int main() { int i; int vis[11000]; for(i=0;i<10000;i++)vis[i+i%10+(i%100)/10+(i%1000)/100+i/1000]=-1; for(i=0;i<10000;i++)if(vis[i]!=-1)cout<<i<<endl; system("pause"); return 0; } Followed by: Post your reply here: |
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