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Re:最强的剪枝In Reply To:Re:最强的剪枝 Posted by:wander_alone at 2013-05-16 15:28:10 > > 算是数据处理吧,哪里算剪枝。。而且,可以做得更好。 > 用数组a存储1-6的石头的个数 > int a[7]; > int b[7] = {1, 60, 30, 20, 15, 12, 10}; > > for(i = 1; i < 7; i++) > a[i] = a[i] % b[i]; 200100 Followed by: Post your reply here: |
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