| ||||||||||
| Online Judge | Problem Set | Authors | Online Contests | User | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest | |||||||||
Re:为何RE!!!!!!!!!!!!!In Reply To:为何RE!!!!!!!!!!!!! Posted by:iamzky at 2013-11-07 08:29:35
#include<cstdio>
#include<cstring>
#include<iostream>
using namespace std;
int a[101][101],i,j,n,minn[101];
bool b[101];
int prim(int s)
{
int i,j,k,ans=0;
memset(minn,0x7f,sizeof(minn));
minn[s]=0;
memset(b,true,sizeof(b));
for(i=1;i<=n;i++)
{
k=0;
for(j=1;j<=n;j++)
if(b[j]&&(minn[j]<minn[k]))
k=j;
b[k]=false;
for(j=1;j<=n;j++)
if((a[k][j]<minn[j])&&b[j]&&a[k][j]!=0)
minn[j]=a[k][j];
}
for(i=1;i<=n;i++)
ans+=minn[i];
return ans;
}
int main()
{
while(scanf("%d",&n)!=EOF)
{
memset(a,0,sizeof(a));
for(i=1;i<=n;i++)
for(j=1;j<=n;j++)
scanf("%d",&a[i][j]);
int ans;
ans=prim(1);
printf("%d\n",ans);
}
return 0;
}
Followed by: Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator