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短小精悍贴个代码,都可以推导的大量?运算可能可读性不好x,y分别代表x,y轴差值 王是x,y中最大值,后是x!=y?1:2,特别注意x==0&&y==0的时候是0,车是x==0||y==0?1:2也是在x&&y==0时是0 最后象稍复杂,观察图不难发现当x,y同奇偶(这时起点终点同色)的时候可到达,不然就是Inf 于是可到达情况下容易得出x==y?1:2 除了王以外其他人跑遍图不超过2步(除了到不了) #include <stdio.h> int main() { int N; char a,c; int b,d,x,y; scanf("%d",&N); getchar(); while(N--) { scanf("%c%d %c%d",&a,&b,&c,&d); getchar(); x=a-c>0?a-c:c-a; y=b-d>0?b-d:d-b; printf("%d %d %d ",x>y?x:y,x==0&&y==0?0:(x==0||y==0?1:(x!=y?2:1)),x==0&&y==0?0:((x==0||y==0)?1:2)); if((x&1)==(y&1)) { printf("%d\n",x==0&&y==0?0:(x==y?1:2)); } else { puts("Inf"); } } } Followed by: Post your reply here: |
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