| ||||||||||
| Online Judge | Problem Set | Authors | Online Contests | User | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest | |||||||||
两个单调队列+哈希,1750MS#include <stdio.h>
#define maxn 50005
int a[maxn];
int s[maxn];
int l[maxn];
int q[maxn], t;
inline int max(int a, int b) {
return a > b ? a : b;
}
int main() {
int n, res;
a[0] = 100005;
while (scanf("%d", &n) != EOF) {
for (int i = 1; i <= n; i++)
scanf("%d", &a[i]);
a[++n] = res = 0;
for (int i = 1, t = 0; i <= n; i++) {
while (t && a[i] < a[q[t]]) {
s[q[t]] = i - 1;
t--;
}
q[++t] = i;
}
for (int i = n - 1, t = 0; i >= 0; i--) {
while (t && a[i] > a[q[t]]) {
l[q[t]] = i + 1;
t--;
}
q[++t] = i;
}
for (int i = 1; i < n; i++)
q[i] = i;
for (int i = 1; i < n; i++) {
while (s[l[i]] < i)
l[i] = s[l[i]] + 1;
q[l[i]] = i;
}
for (int i = 1; i < n; i++)
res = max(res, q[i] - i);
if (res == 0)
res = -1;
printf("%d\n", res);
}
return 0;
}
Followed by: Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator