#include <iostream>
#include <string>
#include <math.h>
#include <sstream>
using namespace std;

const char* Hmonth[19] =
{
 "pop", "no", "zip", "zotz", "tzec", "xul", "yoxkin", "mol", "chen", "yax", 
 "zac", "ceh", "mac", "kankin", "muan", "pax", "koyab", "cumhu","uayet",
};
const char Tday1[20][10] =
{
	"imix","ik","akbal","kan","chicchan","cimi","manik","lamat","muluk",
	"ok","chuen","eb","ben","ix","mem","cib","caban","eznab","canac","ahau",
};
int main()
{
	int n;
	cin>>n;
	for (int i=0; i<n; i++)
	{
		string in1,in2,in3;
		cin>>in1>>in2>>in3;
		int HMonth=0, HDay=0, HYear=0;

		//计算年
		HYear = atoi(in3.c_str());
		//计算H天
		in1.erase(in1.end() - 1);
		HDay = atoi(in1.c_str());
		//计算H月
		for (int j=0; j<19; j++)
		{
			stringstream ss;
			ss<<Hmonth[j];
			string month;
			ss>>month;
			if (in2 == month)
			{
				HMonth = j;
				break;
			}
		}
		
		//计算总天数
		long Allday;
		Allday = HYear*365 + HMonth*20 + HDay + 1;
		

		int TDay1,TDay2,TYear;
		//计算输出年
		TYear = (Allday-1)/260 ;
		Allday -= TYear*260;
		//计算输出天1
		TDay1 = Allday%20;
		if (TDay1 == 0) TDay1 = 20;
		//计算输出天2
		TDay2 = Allday%13;
		if (TDay2 == 0) TDay2 = 13;

		cout<<TDay2<<" "<<Tday1[TDay1 - 1]<<" "<<TYear<<endl;	

	}
	return 0;
}