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Re:119行手写堆维护~忘记传参时怎么传函数了只好把大根堆和小根堆的维护各写一次了QAQ结果我唯一会写的一个数据结构还写错了QAQIn Reply To:119行手写堆维护~忘记传参时怎么传函数了只好把大根堆和小根堆的维护各写一次了QAQ结果我唯一会写的一个数据结构还写错了QAQ Posted by:d891320478 at 2012-09-18 23:46:37 > #include <cstdio> > #include <iostream> > using namespace std; > #define N 1000010 > int pos1[N],pos2[N]; > struct Heap > { > int key,opp; > }heap1[N],heap2[N]; > int n,k; > int ans1[N],ans2[N]; > void build_down1(int father) > { > int son=father*2; > while (son<=k) > { > if(heap1[son+1].key>heap1[son].key && son+1<=k)son++; > if(heap1[son].key>heap1[father].key) > { > swap(pos1[heap1[son].opp],pos1[heap1[father].opp]); > swap(heap1[son],heap1[father]); > } > else return; > father=son; > son=father*2; > } > } > void build_down2(int father) > { > int son=father*2; > while (son<=k) > { > if(heap2[son+1].key<heap2[son].key && son+1<=k)son++; > if(heap2[son].key<heap2[father].key) > { > swap(pos2[heap2[son].opp],pos2[heap2[father].opp]); > swap(heap2[son],heap2[father]); > } > else return; > father=son; > son=father*2; > } > } > void build_up1(int son) > { > int father=son/2; > while (father>=1) > { > if(heap1[father].key<heap1[son].key) > { > swap(pos1[heap1[father].opp],pos1[heap1[son].opp]); > swap(heap1[father],heap1[son]); > } > else break; > son=father; > father=son/2; > } > } > void build_up2(int son) > { > int father=son/2; > while (father>=1) > { > if(heap2[father].key>heap2[son].key) > { > swap(pos2[heap2[father].opp],pos2[heap2[son].opp]); > swap(heap2[father],heap2[son]); > } > else break; > son=father; > father=son/2; > } > } > int main () > { > int i,j; > scanf("%d%d",&n,&k); > for(i=1;i<=k;i++) > { > pos1[i]=pos2[i]=heap1[i].opp=i; > scanf("%d",&heap1[i].key); > heap2[i]=heap1[i]; > } > for(i=k/2;i>=1;i--) > { > build_down1(i); > build_down2(i); > } > ans1[++ans1[0]]=heap1[1].key; > ans2[++ans2[0]]=heap2[1].key; > for(i=k+1;i<=n;i++) > { > int a,b1,b2,zzz=(i%k==0?k:i%k); > scanf("%d",&a); > b1=heap1[pos1[zzz]].key; > b2=heap2[pos2[zzz]].key; > heap1[pos1[zzz]].key=heap2[pos2[zzz]].key=a; > if(a>b1)build_up1(pos1[zzz]); > else build_down1(pos1[zzz]); > if(a<b2)build_up2(pos2[zzz]); > else build_down2(pos2[zzz]); > ans1[++ans1[0]]=heap1[1].key; > ans2[++ans2[0]]=heap2[1].key; > } > for(i=1;i<=ans2[0];i++) > { > printf("%d",ans2[i]); > if(i<ans2[0])printf(" "); > else printf("\n"); > } > for(i=1;i<=ans1[0];i++) > { > printf("%d",ans1[i]); > if(i<ans1[0])printf(" "); > else printf("\n"); > } > > return 0; > }挽 Followed by: Post your reply here: |
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