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Re:电话号码翻译In Reply To:Re:电话号码翻译 Posted by:20072631 at 2008-10-12 09:03:36 > 代码 > C > #include<stdio.h> > #include<string.h> > struct unit > { int upset[2]; > > int count; > } > main() > { struct unit b[1510]; > > int i,j,flag1,flag2=0,flag3=0,m,n; > > static int k=0,temper,counter=0,temp[22]; > > char number[22]; > > static int zancun[2]; > > for(i=0;i<1510;i++) > { > b[i].upset[0]=-1; > > b[i].count=1; > } > > printf("Error:\n"); /*xian shu chu error*/ > > while(gets(number)!=NULL) > > { > if(number[0]!='3'&&number[0]!='6' > &&number[0]!='D'&&number[0]!='E' > &&number[0]!='F'&&number[0]!='M' > &&number[0]!='N'&&number[0]!='O') > > { > abc:printf("%s\n",number); > > flag2=1; > continue; > } /*shou wei bu shi 3 6 zhi jie shu chu*/ > else > { > > > for(i=0,j=0,k=0;number[i]!='\0';i++) > > { > if(number[i]=='A'||number[i]=='B'|| > number[i]=='C'|| > number[i]=='2') > { > temp[k++]=2;j++; continue; > } > if(number[i]=='D'||number[i]=='E'||number[i]=='F'||number[i]=='3') > { > temp[k++]=3;j++; continue; > } > if(number[i]=='G'||number[i]=='H'||number[i]=='I'||number[i]=='4') > { > temp[k++]=4;j++;continue; > } > if(number[i]=='J'||number[i]=='K'||number[i]=='L'||number[i]=='5') > { > temp[k++]=5;j++; continue; > } > if(number[i]=='M'||number[i]=='N'||number[i]=='O'||number[i]=='6') > { > temp[k++]=6;j++; continue; > } > if(number[i]=='P'||number[i]=='R'||number[i]=='S'||number[i]=='7') > { > temp[k++]=7;j++; continue; > } > if(number[i]=='T'||number[i]=='U'||number[i]=='V'||number[i]=='8') > { > temp[k++]=8;j++; continue; > } > if(number[i]=='W'||number[i]=='X'||number[i]=='Y'||number[i]=='9') > { > temp[k++]=9; j++; continue; > } > > if(number[i]=='1') > { > temp[k++]=1; j++; continue; > } > if(number[i]=='0') > { > temp[k++]=0; j++;continue; > } > if(number[i]=='Q'||number[i]=='Z') > goto abc; /*ba shu zi yiyi dui ying */ > > if(j>6) > > goto abc; /*pan duan wei shu*/ > > temp[k]=-1; > } > /*chu ru yi ge dian hua zhi*/ > > flag1=0; > > m=100*temp[0]+10*temp[1]+temp[2]; > > n=1000*temp[3]+100*temp[4]+10*temp[5]+temp[6]; > > for(i=0;b[i].upset[0]!=-1;i++) > > { > if(b[i].upset[0]==m) > > if(b[i].upset[1]==n) > > { > (b[i].count)++; > > flag1=1; > > flag3=1; > } > > } > if(flag1==0) > { > > > b[counter].upset[0]=m; > > > > b[counter].upset[1]=n; > > counter++; > } > } > } > if(flag2==0) > > printf("Not found.\n"); > > printf("\nDuplication:\n"); > > if(flag3==0) > > printf("Not found.\n"); > > else { > for(i=0;i<counter;i++) > > for(j=0;j<counter-1;j++ ) > > { > if(b[i].upset[0]<b[j].upset[0]) > > { > zancun[0] = b[i].upset[0]; > zancun[1]=b[i].upset[1]; > temper=b[i].count; > > > b[i].upset[0]=b[j].upset[0]; > b[i].upset[1]=b[j].upset[1]; > b[i].count=b[j].count; > > > b[j].upset[0]=zancun[0]; > b[j].upset[1]=zancun[1]; > b[j].count=temper; > } > if(b[i].upset[0]==b[j].upset[0]) > { > if(b[i].upset[1]<b[j].upset[1]) > > { > zancun[0] = b[i].upset[0]; > zancun[1]=b[i].upset[1]; > temper=b[i].count; > > > b[i].upset[0]=b[j].upset[0]; > b[i].upset[1]=b[j].upset[1]; > b[i].count=b[j].count; > > > b[j].upset[0]=zancun[0]; > b[j].upset[1]=zancun[1]; > b[j].count=temper; > } > } > } > > for(i=0;i<counter;i++) > { > if(b[i].count!=1) > > { > > printf("%0.3d",b[i].upset[0]); > > printf("-"); > > printf("%0.4d",b[i].upset[1]); > > printf(" %d\n",b[i].count); > > } > } > > } > } Followed by: Post your reply here: |
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