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Re:请教 WA的有点郁闷In Reply To:请教 WA的有点郁闷 Posted by:Nstd at 2010-05-23 14:01:29 > 这样能过: > > #include "stdio.h" > #include<string.h> > int main() > { > char key[15],ip[105],turn[15][15],i; > int j,a,b,keylen,iplen,p; > while(scanf("%s",key)!=EOF && strcmp(key,"THEEND")){ > scanf("%s",ip); > keylen=strlen(key); > iplen=strlen(ip); > b=iplen/keylen; > p=0; > > for(i='A';i<='Z';i++) > for(j=0;key[j];j++) > if(i==key[j]) > for(a=0;a<b;a++,p++) > turn[a][j]=ip[p]; > > for(i=0;i<b;i++)//以字符一个一个地输出 > for(j=0;j<keylen;j++) > printf("%c",turn[i][j]); > puts(""); > > } > return 0; > } > > 这样就过不了: > > #include "stdio.h" > #include<string.h> > int main() > { > char key[15],ip[105],turn[15][15],i; > int j,a,b,keylen,iplen,p; > while(scanf("%s",key)!=EOF && strcmp(key,"THEEND")){ > scanf("%s",ip); > keylen=strlen(key); > iplen=strlen(ip); > b=iplen/keylen; > p=0; > > for(i=0;i<keylen;i++) //上面的程序修改的是这个地方,这里是当成字符串来输出,上面是一个一个字符地输出 > turn[i][keylen]=0; > > for(i='A';i<='Z';i++) > for(j=0;key[j];j++) > if(i==key[j]) > for(a=0;a<b;a++,p++) > turn[a][j]=ip[p]; > > for(i=0;i<b;i++)//以字符串一个单位一个单位地输出 > printf("%s",turn[i]); > puts(""); > > } > return 0; > } Followed by: Post your reply here: |
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