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Re:妙啊！

Posted by guowentian at 2013-08-13 09:51:55 on Problem 2142
In Reply To:妙啊！ Posted by:swust20064469 at 2009-07-14 10:40:45

> 设a>b之后
> |x0+b/d *t| 单调递增，|y0-a/d*t| 先递减再递增。因斜率a/d>b/d，所以总的|x0+b/d *t |+|y0-a/d *t| 先递减再递增，使y0-a/d*t0=0 的t0附近有最小值。
|y0-a/d*t| 先递减再递增 为何??

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