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枚举+kruskal, 每次更新最小值即可,一次AC,估计把样例过了就能ac,AC代码见下#include<stdio.h> #include<stdlib.h> #include<string.h> #include<limits.h> typedef struct { int x; int y; int w; }init; int cmp(const void *a, const void *b) { init *c=(init *)a; init *d=(init *)b; return c->w - d->w; } int p[105]; void set() { for(int i=0;i<105;i++) p[i]=i; } int find(int x) { int s=x; while(s!=p[x]) { s=p[x]; x=p[s]; } return p[x]; } int main() { int n,m,i,j,min,flag,t,count; init map[5005]; while(scanf("%d%d",&n,&m),n+m) { memset(map,0,sizeof(map)); min=INT_MAX; flag=0; for(i=0;i<m;i++) { scanf("%d%d%d",&map[i].x,&map[i].y,&map[i].w); } qsort(map,5005,sizeof(map[0]),cmp); for(i=0;!map[i].w;i++); for(t=0;t<m-n+2;t++) { set(); for(j=i,count=0;j<5005;j++) { int f1=find(map[j].x); int f2=find(map[j].y); if(f1 != f2) { p[f1]=f2; count++; } if(count == n-1) { flag=1; if(map[j].w - map[i].w <min) min=map[j].w - map[i].w; i++; break; } } } if(flag) printf("%d\n",min); else printf("-1\n"); } return 0; } Followed by: Post your reply here: |
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