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Re:为什么着题总超时啊,用的是宽搜,大牛门用的是什么算法,还是有好的减枝?In Reply To:为什么着题总超时啊,用的是宽搜,大牛门用的是什么算法,还是有好的减枝? Posted by:fjnu_jxd_010 at 2005-10-06 16:09:31 我的code
#include<iostream>
//#include<memory.h>
using namespace std;
/*int as(int t,int i,int sum,int head,int tail)
{
if(head>tail) return 0;
t=s[head];
int j;
if(sum>m)return 0;
if(i==n+1)
{
if(sum<=m&&b[sum]==0)
{max++;b[sum]=1;}
return 0;
}
t++;
for(j=0;j<=num[i];j++)
as(t,i+1,sum+j*a[i]);
// i++;
return 0;
}
*/
typedef struct node
{
int we;
int sn[103];
}node ;
node s[10005];
int main()
{
int a[2003],ma,n,m,j,ta,b[150008],num[2003],cw;
int i,head,tail;
while(scanf("%d%d",&n,&m)==2&&(n||m))
{
head=0;tail=0;ta=0;
ma=0;
memset(b,0,sizeof(int)*(m+2));
memset(s,0,sizeof(s));
for(i=1;i<=n;i++)
scanf("%d",&a[i]);
for(i=1;i<=n;i++)
scanf("%d",&num[i]);
while(head+ta*10000<=tail+ma*10000)
{
for(i=1;i<=n;i++)
if(s[head].sn[i]<num[i])
{
cw=s[head].we+a[i];
if(cw<=m)
if(!b[cw])
{
tail++;
if(tail==10001)
{ tail=1;ma++;}
s[tail].we=cw;b[cw]=1;
for(j=1;j<=n;j++)
s[tail].sn[j]=s[head].sn[j];
s[tail].sn[i]++;
}
}
head++;
if(head==10001)
{head=1;ta++;}
}
//as(1,0,head,tail);
printf("%d\n",tail+30000*ma);
}
return 0;
}
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